Chapter 2 (Balbharati) · Class 8 Maharashtra SSC · Formula Sheet

Parallel Lines and Transversal (समांतर रेषा आणि छेदिका) Formulas — Class 8 Maharashtra SSC

Properties of parallel lines cut by a transversal, corresponding and alternate angles.

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Worked Examples

1Using: Supplementary Angles

If one angle is 65 degrees, find its supplement.

Step 1: Supplement = 180 - 65

Step 2: = 115 degrees.

Answer: 115 degrees

2Using: Vertically Opposite

Two lines intersect. If one angle is 40 degrees, find the vertically opposite angle.

Step 1: Vertically opposite angles are equal.

Step 2: The angle = 40 degrees.

Answer: 40 degrees

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More Class 8 Maharashtra SSC Formulas

Rational and Irrational Numbers (परिमेय आणि अपरिमेय संख्या)Indices and Cube Root (घातांक आणि घनमूळ)Altitudes and Medians of a Triangle (त्रिकोणाची उंची आणि मध्यगा)Expansion Formulae (विस्तार सूत्रे)Factorisation (अवयवीकरण)Variation (चलन)

Frequently Asked Questions

How many formulas are in Class 8 Maharashtra SSC Parallel Lines and Transversal (समांतर रेषा आणि छेदिका)?+
There are several key formulas in the Parallel Lines and Transversal (समांतर रेषा आणि छेदिका) chapter for Class 8 Maharashtra SSC. Each formula is essential for solving problems in this topic.
How to remember Parallel Lines and Transversal (समांतर रेषा आणि छेदिका) formulas easily?+
Practice regularly with worked examples, group related formulas together, and use SparkEd's interactive practice mode to reinforce your memory through problem-solving.
Are these Parallel Lines and Transversal (समांतर रेषा आणि छेदिका) formulas enough for exams?+
Yes, these formulas cover the complete Maharashtra SSC Class 8 syllabus for Parallel Lines and Transversal (समांतर रेषा आणि छेदिका). Practice applying them to different types of questions for full exam readiness.

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