Number Play MCQ Test — Class 6 CBSE

Solution:

To form the greatest number using given digits, place the largest digit at the thousands place, the next largest at the hundreds place, and so on.

The given digits are 7, 0, 8, 3. The largest digit is 8.

Arranging them in descending order: 8, 7, 3, 0.

Therefore, the greatest 4-digit number is 8730.

Solution:

The given number is 5,34,892 in the Indian System.

The digit '3' is in the ten thousands place. So, its place value is 3 × 10,000 = 30,000.

The face value of the digit '9' is simply 9.

The difference between the place value of '3' and the face value of '9' is 30,000 - 9 = 29,991.

Solution:

In the International System, numbers are grouped into sets of three digits from the right, separated by commas (e.g., Millions, Thousands, Ones).

'Seventy-five million' means 75,000,000.

'Two hundred nine thousand' means 209,000.

'Four hundred sixteen' means 416. Combining these gives 75,209,416.

Solution:

To round a number to the nearest hundred, we look at the digit in the tens place.

The number is 2,387. The digit in the tens place is 8.

Since 8 is 5 or greater, we round up the hundreds digit. The hundreds digit '3' becomes '4'.

All digits to the right of the hundreds place become 0. So, 2,387 rounded to the nearest hundred is 2,400.

Solution:

To round a number to the nearest thousand, we look at the digit in the hundreds place.

The number of books is 4,567. The digit in the hundreds place is 5.

Since 5 is 5 or greater, we round up the thousands digit. The thousands digit '4' becomes '5'.

All digits to the right of the thousands place become 0. So, 4,567 rounded to the nearest thousand is 5,000.

Solution:

According to the order of operations (BODMAS/PEMDAS), we first solve the expression inside the brackets.

12 - 4 = 8.

Now the expression becomes 15 × 8 + 2.

Next, perform multiplication: 15 × 8 = 120. Finally, perform addition: 120 + 2 = 122.

Solution:

To write 94 in Roman numerals, break it down into tens and ones.

90 is written as XC (100 - 10).

4 is written as IV (5 - 1).

Combining them, 94 is written as XCIV.

Solution:

Natural numbers start from 1 (1, 2, 3, ...).

Whole numbers start from 0 (0, 1, 2, 3, ...).

Since whole numbers include 0 and all natural numbers, all natural numbers are indeed whole numbers.

Zero is not a natural number, and natural numbers do not include negative numbers.

Solution:

The associative property of addition states that the way in which three or more numbers are grouped for addition does not affect the sum.

Ravi grouped (5 + 8) + 2, while Priya grouped 5 + (8 + 2).

Both methods yield the same result (15), demonstrating the associative property of addition.

The commutative property refers to changing the order (e.g., a+b = b+a), not the grouping.

Solution:

Starting from 0.

Moving 3 steps to the right from 0 means adding 3: 0 + 3 = 3.

From 3, moving 4 steps to the left means subtracting 4: 3 - 4 = -1.

The student will finally be at -1.