How many practice questions are available for Statistics?

SparkEd Math offers 0+ practice questions for Statistics across 3 difficulty levels (Easy, Medium, Hard) plus a timed test mode. Each question comes with visual step-by-step solutions and AI coaching hints.

Is Statistics content free on SparkEd Math?

Yes! All Statistics content on SparkEd Math is 100% free, including practice questions, visual solutions, lessons, and AI coaching. No credit card required.

How does SparkEd Math teach Statistics differently from textbooks?

SparkEd Math uses visual step-by-step solutions for every Statistics problem, making complex concepts easy to understand. The platform includes 3 difficulty levels for progressive learning, a Super Power Help AI coach for instant doubt-clearing, and interactive practice rather than passive reading.

Is SparkEd's Statistics content aligned with the CBSE syllabus?

Yes, all Statistics questions and lessons on SparkEd Math are fully aligned with the Central Board of Secondary Education (CBSE) syllabus for Class 10. The content follows the official curriculum structure and exam pattern.

Statistics — Class 10 CBSE (2025-26)

About Statistics — Class 10 CBSE

Compute mean, median, and mode of grouped data; draw cumulative frequency curves (ogives). This topic is part of the CBSE Class 10 mathematics syllabus (chapter: Chapter 13). On this page you can practice 60 questions across three difficulty levels — 20 easy, 20 medium, and 20 hard — each with a visual step-by-step solution, plus a timed 35-question mastery test with a live leaderboard. Worked examples and sample questions from the topic are below.

Statistics — solved examples for Class 10 CBSE

Example 1easy

The mean of 5 numbers is 20. What is the sum of these 5 numbers?

A)80
B)100
C)25
D)4

Step-by-step solution

Sum = Mean $\times$ Number of observations
$= 20 \times 5 = 100$

Answer: 100

Example 2medium

Find the mean using the direct method for the following data:
| Class |

0-10

10-20

20-30

30-40

|
| Frequency | 5 | 8 | 12 | 5 |

A)18.5
B)20.67
C)20
D)17.5

Step-by-step solution

Class marks: 5, 15, 25, 35
$\sum f_i x_i = 5(5)+8(15)+12(25)+5(35) = 25+120+300+175 = 620$
$N = 5+8+12+5 = 30$
Mean $= 620/30$
$\approx 20.67$

Answer: 20.67

Example 3hard

Find the median of the following data:
| Class |

0-10

10-20

20-30

30-40

40-50

|
| Freq | 5 | 8 | 20 | 7 | 10 |

A)24.5
B)25.0
C)23.0
D)26.0

Step-by-step solution

$N = 50$ , $N/2 = 25$ .
cf: 5, 13, 33, 40, 50. Median class: $20-30$ (cf first $\ge 25$ ).
$l = 20, cf = 13, f = 20, h = 10$
Median $= 20 + \frac{25-13}{20} \times 10 = 20 + 6$
$= 26$

Answer: 26.0

Practice questions on Statistics

Q1.easy
The class mark of the class interval $10 - 20$ is:
1. A)10
2. B)20
3. C)15
4. D)30
Show answer
Answer: 15
Hint: Class mark = (upper limit + lower limit) / 2.
Q2.easy
In a frequency distribution, the sum of $f_i x_i = 420$ and $\sum f_i = 30$ . The mean is:
1. A)12
2. B)14
3. C)15
4. D)16
Show answer
Answer: 14
Hint: Mean (direct method) $= \frac{\sum f_i x_i}{\sum f_i}$ .
Q3.easy
The mode of the data: 2, 3, 4, 5, 3, 3, 4, 2, 3 is:
1. A)2
2. B)3
3. C)4
4. D)5
Show answer
Answer: 3
Hint: Mode is the value that appears most frequently.
Q4.medium
Using the assumed mean method with $a = 25$ , find $\sum f_i d_i$ if the class marks are 5, 15, 25, 35, 45 with frequencies 6, 10, 12, 8, 4.
1. A) $-60$
2. B) $-100$
3. C) $80$
4. D) $100$
Show answer
Answer: $-60$
Hint: $d_i = x_i - a$ . Find each $d_i$ , multiply by $f_i$ , and sum.
Q5.medium
Find the mode of the following grouped data:
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
| Frequency | 5 | 8 | 15 | 10 | 2 |
1. A)25.0
2. B)24.17
3. C)23.33
4. D)26.67
Show answer
Answer: 24.17
Hint: Modal class = 20-30 (highest frequency 15). Use the mode formula.
Q6.medium
The cumulative frequency just before the median class is called:
1. A) $cf$
2. B) $f$
3. C)Class mark
4. D)Assumed mean
Show answer
Answer: $cf$
Hint: In the median formula, $cf$ is the cumulative frequency of the class preceding the median class.
Q7.hard
The mean of the following distribution is 50. Find the missing frequencies $f_1$ and $f_2$ if total frequency is 120.
| Class | $0-20$ | $20-40$ | $40-60$ | $60-80$ | $80-100$ |
| Freq | 17 | $f_1$ | 32 | $f_2$ | 19 |
1. A) $f_1 = 28, f_2 = 24$
2. B) $f_1 = 24, f_2 = 28$
3. C) $f_1 = 30, f_2 = 22$
4. D) $f_1 = 26, f_2 = 26$
Show answer
Answer: $f_1 = 28, f_2 = 24$
Hint: Use two equations: $f_1 + f_2 = 52$ and $\sum f_i x_i / 120 = 50$ .
Q8.hard
Find the mean using step deviation method:
| Class | $5-15$ | $15-25$ | $25-35$ | $35-45$ | $45-55$ |
| Freq | 6 | 11 | 21 | 7 | 5 |
1. A)27
2. B)28.8
3. C)29
4. D)30
Show answer
Answer: 28.8
Hint: Take $a = 30$ and $h = 10$ . Find $u_i$ values and compute.
Q9.hard
Find the median from:
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ |
| Freq | 5 | 10 | 20 | 15 | 10 | 5 |
1. A)28.75
2. B)28.5
3. C)30.0
4. D)29.0
Show answer
Answer: 28.75
Hint: $N = 65, N/2 = 32.5$ . Build cf and find the median class.

These are 9 of the 60 questions available for Statistics. Start practicing above to unlock visual solutions, AI coaching, and the topic leaderboard — completely free.