Example 1easy
- A)Prisha is incorrect because the domain of a rational function excludes values that make the numerator zero. Here, x = 5 would make the numerator zero.
- B)Prisha is incorrect because the domain of a rational function excludes values that make the denominator zero. Here, x = 5 would make the denominator zero.
- C)Prisha is incorrect because the domain of a rational function excludes values that make the function negative. Here, x = 4 would make the function negative.
- D)Prisha is incorrect because the domain of a rational function excludes values that make the function undefined, but x = 5 makes the function defined as zero.
Step-by-step solution
- Step 1: Understand the definition of the domain for a rational function. The domain is the set of all possible input values (x) for which the function is defined.
- Step 2: Identify potential restrictions for rational functions. A rational function, which is a ratio of two polynomials, becomes undefined if its denominator is equal to zero.
- Step 3: Apply this rule to f(x) = 1/(x - 5). The denominator is (x - 5). Setting the denominator to zero gives x - 5 = 0, which means x = 5. Therefore, x = 5 must be excluded from the domain.
- Step 4: Conclude that Prisha's statement is incorrect because the domain excludes x = 5, making option B the correct explanation.
Answer: Prisha is incorrect because the domain of a rational function excludes values that make the denominator zero. Here, x = 5 would make the denominator zero.