Loading...

About Simple Equations — Class 6 ICSE

Learn to form and solve linear equations in one variable using transposition and balancing methods. This topic is part of the ICSE Class 6 mathematics syllabus (chapter: Chapter 13). On this page you can practice 60 questions across three difficulty levels — 20 easy, 20 medium, and 20 hard — each with a visual step-by-step solution, plus a timed 20-question mastery test with a live leaderboard. Worked examples and sample questions from the topic are below.

What you'll learn in Simple Equations

  • What is an Equation?
  • LHS, RHS and Solutions
  • Rule 1 — Adding & Subtracting Both Sides
  • Rule 2 — Multiplying & Dividing Both Sides
  • Rule of Transposition
  • Solving Multi-Step Equations
  • Word Problems with Simple Equations

Interactive lesson · about 20 minutes · checkpoint question after every unit

Simple Equations — solved examples for Class 6 ICSE

Example 1easy

Solve: x−4=8x - 4 = 8
  1. A)4
  2. B)8
  3. C)12
  4. D)−4

Step-by-step solution

  1. We have x−4=8x - 4 = 8.
  2. Add 4 to both sides: x=8+4x = 8 + 4
  3. Therefore:
    x=12x = 12

Answer: 12

Example 2medium

Solve: 5x+4=195x + 4 = 19
  1. A)2
  2. B)3
  3. C)4
  4. D)5

Step-by-step solution

  1. We have 5x+4=195x + 4 = 19.
  2. Subtract 4 from both sides: 5x=155x = 15
  3. Divide by 5:
    x=3x = 3

Answer: 3

Example 3hard

Solve: 7(3x−1)−6(2x+3)=8(x−2)+17(3x - 1) - 6(2x + 3) = 8(x - 2) + 1
  1. A)−8
  2. B)8
  3. C)−10
  4. D)10

Step-by-step solution

  1. Expand: 21x−7−12x−18=8x−16+121x - 7 - 12x - 18 = 8x - 16 + 1
  2. Simplify: 9x−25=8x−159x - 25 = 8x - 15
  3. Transpose 8x8x to the left and −25-25 to the right: x=−15+25x = -15 + 25
  4. Therefore:
    x=10x = 10

Answer: 10

Practice questions on Simple Equations

  1. Q1.easy

    Solve: x+7=2x + 7 = 2
    1. A)9
    2. B)5
    3. C)−5
    4. D)−9
    Show answer

    Answer: −5

    Hint: Subtract 7 from both sides.

  2. Q2.easy

    Solve: x−6=−3x - 6 = -3
    1. A)3
    2. B)−3
    3. C)−9
    4. D)9
    Show answer

    Answer: 3

    Hint: Add 6 to both sides.

  3. Q3.easy

    Solve: y+2=−6y + 2 = -6
    1. A)−8
    2. B)−4
    3. C)4
    4. D)8
    Show answer

    Answer: −8

    Hint: Subtract 2 from both sides.

  4. Q4.medium

    Solve: −6+3x=−5-6 + 3x = -5
    1. A)13\dfrac{1}{3}
    2. B)−13-\dfrac{1}{3}
    3. C)113\dfrac{11}{3}
    4. D)−113-\dfrac{11}{3}
    Show answer

    Answer: 13\dfrac{1}{3}

    Hint: Add 6 to both sides, then divide by 3.

  5. Q5.medium

    Solve: 2x+12=3−x2x + 12 = 3 - x
    1. A)−3
    2. B)3
    3. C)5
    4. D)−5
    Show answer

    Answer: −3

    Hint: Move all x terms to one side and constants to the other.

  6. Q6.medium

    Solve: x5+5=2\dfrac{x}{5} + 5 = 2
    1. A)−15
    2. B)15
    3. C)−35
    4. D)35
    Show answer

    Answer: −15

    Hint: Subtract 5 from both sides, then multiply by 5.

  7. Q7.hard

    Solve: x−13=x+22\dfrac{x - 1}{3} = \dfrac{x + 2}{2}
    1. A)−8
    2. B)8
    3. C)−4
    4. D)4
    Show answer

    Answer: −8

    Hint: Cross-multiply: 2(x−1)=3(x+2)2(x-1) = 3(x+2).

  8. Q8.hard

    If 4x+3=154x + 3 = 15, then the value of 2x−32x - 3 is:
    1. A)3
    2. B)6
    3. C)9
    4. D)12
    Show answer

    Answer: 3

    Hint: First find xx from 4x+3=154x + 3 = 15, then substitute into 2x−32x - 3.

  9. Q9.hard

    If x2+3=5−x\dfrac{x}{2} + 3 = 5 - x, then xx equals:
    1. A)43\dfrac{4}{3}
    2. B)34\dfrac{3}{4}
    3. C)23\dfrac{2}{3}
    4. D)32\dfrac{3}{2}
    Show answer

    Answer: 43\dfrac{4}{3}

    Hint: Multiply all terms by 2 to clear the fraction.

These are 9 of the 60 questions available for Simple Equations. Start practicing above to unlock visual solutions, AI coaching, and the topic leaderboard — completely free.