Example 1easy
Step-by-step solution
- c² = 3² + 4² = 9 + 16 = 25
- c = √25 = 5 cm
Answer: 5
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Apply the Pythagorean theorem and its converse to solve geometric problems. This topic is part of the IB Class 8 mathematics syllabus (chapter: Unit 12). On this page you can practice 60 questions across three difficulty levels — 20 easy, 20 medium, and 20 hard — each with a visual step-by-step solution, plus a timed 35-question mastery test with a live leaderboard. Worked examples and sample questions from the topic are below.
Step-by-step solution
Answer: 5
Step-by-step solution
Answer: 10
Step-by-step solution
Answer: Yes, P is on the bridge
Q1.easy
Answer: 10
Hint: \(c^2 = 36 + 64\).
Q2.easy
Answer: 12
Hint: \(b^2 = c^2 - a^2 = 169 - 25\).
Q3.easy
Answer: Yes
Hint: Check if 7² + 24² = 25².
Q4.medium
Answer: 12
Hint: The height bisects the base, creating a right triangle with hypotenuse 13 and base 5.
Q5.medium
Answer: 25
Hint: North and east are perpendicular. Distance = \(\sqrt{15^2 + 20^2}\).
Q6.medium
Answer: 12
Hint: \(w = \sqrt{15^2 - 9^2}\).
Q7.hard
Answer: 14.1
Hint: Space diagonal = \(\sqrt{6^2 + 8^2 + 10^2}\).
Q8.hard
Answer: 26
Hint: Height difference = 10 m. Distance between tops = √(24² + 10²).
Q9.hard
Answer: 8
Hint: The slant height connects the apex to the midpoint of a base edge. Distance from centre to midpoint of edge = 6 cm.
These are 9 of the 60 questions available for Pythagorean Theorem. Start practicing above to unlock visual solutions, AI coaching, and the topic leaderboard — completely free.