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About Logarithms — Class 9 IB

Define logarithms, apply laws of logarithms, and solve exponential equations. This topic is part of the IB Class 9 mathematics syllabus (chapter: Unit 12). On this page you can practice 59 questions across three difficulty levels — 20 easy, 19 medium, and 20 hard — each with a visual step-by-step solution, plus a timed 35-question mastery test with a live leaderboard. Worked examples and sample questions from the topic are below.

Logarithms — solved examples for Class 9 IB

Example 1easy

Convert the exponential equation 5^3 = 125 into its equivalent logarithmic form.
  1. A)log_3(125) = 5
  2. B)log_5(3) = 125
  3. C)log_125(5) = 3
  4. D)log_5(125) = 3

Step-by-step solution

  1. The general definition of a logarithm states that if b^c = a, then log_b(a) = c.
  2. In the given exponential equation, 5^3 = 125, we have the base b = 5, the exponent c = 3, and the result a = 125.
  3. Applying the definition, we convert it to log_5(125) = 3.

Answer: log_5(125) = 3

Example 2medium

If 7^y = 343, which of the following logarithmic equations correctly represents the value of y?
  1. A)log_343(7) = y
  2. B)log_7(y) = 343
  3. C)log_y(343) = 7
  4. D)log_7(343) = y

Step-by-step solution

  1. The definition of a logarithm states that if an exponential equation is given as b^x = N, it can be rewritten in logarithmic form as log_b(N) = x.
  2. In the given equation, 7^y = 343, we have b = 7, x = y, and N = 343.
  3. Applying the definition, the logarithmic form will be log_7(343) = y.

Answer: log_7(343) = y

Example 3hard

Which of the following statements about logarithms is always true for any real numbers a, b, and x?
  1. A)log_b(a) is defined for any a > 0.
  2. B)log_b(a) is defined for any b ≠ 1.
  3. C)log_b(a) is defined only when a > 0, b > 0, and b ≠ 1.
  4. D)log_b(a) is defined for all a and b.

Step-by-step solution

  1. The definition of a logarithm, log_b(a) = x if and only if b^x = a, imposes specific conditions on 'a' and 'b'.
  2. For b^x to consistently map to positive values 'a' and to avoid undefined cases, the base 'b' must be positive (b > 0) and not equal to 1 (b ≠ 1).
    b>0,b1b > 0, b ≠ 1
  3. Consequently, the argument 'a' must always be positive (a > 0), as a positive base raised to any real power will always yield a positive result.
    a>0a > 0
  4. Therefore, the statement 'log_b(a) is defined only when a > 0, b > 0, and b ≠ 1' is the only one that is always true.

Answer: log_b(a) is defined only when a > 0, b > 0, and b ≠ 1.

Practice questions on Logarithms

  1. Q1.easy

    Which of the following statements correctly explains why log_7(1) = 0?
    1. A)Because 7^0 = 1, and the logarithm is the exponent.
    2. B)Because 7 × 0 = 1, and logarithms are about multiplication.
    3. C)Because 7 ÷ 1 = 7, and logarithms are about division.
    4. D)Because 7 + 0 = 7, and logarithms are about addition.
    Show answer

    Answer: Because 7^0 = 1, and the logarithm is the exponent.

    Hint: Recall the definition of a logarithm: log_b(a) = c means b^c = a. What power of any number (except 0) gives 1?

  2. Q2.easy

    A student claimed that log_9(9) = 9. Identify the mistake in their reasoning.
    1. A)The base of the logarithm should be 1, not 9.
    2. B)log_9(9) equals 1, because 9 raised to the power of 1 gives 9.
    3. C)log_9(9) equals 0, because any number raised to the power of 0 is 1.
    4. D)The number inside the logarithm must be different from the base.
    Show answer

    Answer: log_9(9) equals 1, because 9 raised to the power of 1 gives 9.

    Hint: Think about what exponent you would put on the base to get the number inside the logarithm.

  3. Q3.easy

    Evaluate log_4(64).
    1. A)2
    2. B)3
    3. C)4
    4. D)16
    Show answer

    Answer: 3

    Hint: Ask yourself: 'What power must 4 be raised to in order to get 64?'

  4. Q4.medium

    Simplify the expression: log(x^3 y^2 / z^4), assuming base 10.
    1. A)3log(x) + 2log(y) + 4log(z)
    2. B)3log(x) + 2log(y) - 4log(z)
    3. C)log(x^3) + log(y^2) / log(z^4)
    4. D)log(x) + log(y) - log(z)
    Show answer

    Answer: 3log(x) + 2log(y) - 4log(z)

    Hint: Apply the product, quotient, and power rules of logarithms step-by-step. Remember that division implies subtraction of logarithms.

  5. Q5.medium

    Evaluate the expression: log_2(16) + log_3(1/27) - log_5(√5).
    1. A)4
    2. B)0.5
    3. C)-0.5
    4. D)1.5
    Show answer

    Answer: 0.5

    Hint: Express each number as a power of its base. Remember that 1/a^n = a^(-n) and √a = a^(1/2).

  6. Q6.medium

    Solve for x: 5^(x-2) = 125.
    1. A)x = 3
    2. B)x = 4
    3. C)x = 5
    4. D)x = 25
    Show answer

    Answer: x = 5

    Hint: Try to express both sides of the equation with the same base. Recognize that 125 is a power of 5.

  7. Q7.hard

    Simplify the expression: 3 × log_2(16) + 2 × log_3(1/9) - log_5(√125).
    1. A)10
    2. B)5
    3. C)0
    4. D)-1
    Show answer

    Answer: 5

    Hint: Convert each term into a simpler logarithmic form using the definition and properties, then evaluate the logarithms individually.

  8. Q8.hard

    If 7^(x-1) = 3^(2x+1), find the value of x correct to two decimal places.
    1. A)1.34
    2. B)-1.34
    3. C)0.87
    4. D)-0.87
    Show answer

    Answer: -0.87

    Hint: Take the logarithm of both sides of the equation to bring down the exponents. Remember to use the power rule of logarithms.

  9. Q9.hard

    Given that log_b(a) = X and log_b(c) = Y, show that log_b( (a^3 × c) / b^2 ) can be expressed as 3X + Y - 2.
    1. A)The statement is always true.
    2. B)The statement is true only if b = 10.
    3. C)The statement is false, the correct expression is 3X + Y + 2.
    4. D)The statement is false, the correct expression is (3X + Y) / 2.
    Show answer

    Answer: The statement is always true.

    Hint: Apply the logarithm laws for product, quotient, and power, and remember the value of log_b(b).

These are 9 of the 59 questions available for Logarithms. Start practicing above to unlock visual solutions, AI coaching, and the topic leaderboard — completely free.