Example 1easy
- A)DE is parallel to BC and DE = BC
- B)DE is perpendicular to BC and DE = (1/2) × BC
- C)DE is parallel to AC and DE = (1/2) × BC
- D)DE is parallel to BC and DE = (1/2) × BC
Step-by-step solution
- The Mid-Point Theorem states that the line segment joining the mid-points of two sides of a triangle is parallel to the third side and is half of the length of the third side.
- In triangle ABC, if D and E are mid-points of AB and AC respectively, then the segment DE must be parallel to BC and its length must be half of BC.
Answer: DE is parallel to BC and DE = (1/2) × BC