Example 1easy
- A)P(E) > 1
- B)P(E) < 0
- C)0 ≤ P(E) ≤ 1
- D)P(E) = 1.5
Step-by-step solution
- The probability of any event E, denoted as P(E), represents the likelihood of that event occurring.
- By definition, the number of favourable outcomes n(E) cannot be negative and cannot exceed the total number of outcomes n(S).
- Therefore, 0 ≤ n(E) ≤ n(S).
- Dividing by n(S), we get 0/n(S) ≤ n(E)/n(S) ≤ n(S)/n(S), which simplifies to 0 ≤ P(E) ≤ 1.
Answer: 0 ≤ P(E) ≤ 1