Solved example 1
For what value of k will the pair of equations kx + 3y = k − 3 and 12x + ky = k have no solution?Step-by-step solution
- a₁/a₂ = k/12, b₁/b₂ = 3/k
- For parallel lines: k/12 = 3/k → k² = 36 → k = ±6
- Check k = 6: c₁/c₂ = 3/6 = 1/2 = a₁/a₂. So all ratios equal → infinitely many solutions.
- Check k = −6: a₁/a₂ = −1/2, c₁/c₂ = −9/−6 = 3/2 ≠ −1/2. No solution ✓
- k = −6.
Answer: -6