How to Solve Direct and Inverse Proportions — Step by Step Guide
Identify and solve problems involving direct and inverse variation. This guide covers Class 8 to 8.
Step-by-Step Method
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Direct proportion: when one quantity increases, the other also increases at the same rate. x/y = constant.
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Inverse proportion: when one quantity increases, the other decreases. x × y = constant.
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For direct proportion: x₁/y₁ = x₂/y₂. Cross multiply to find the unknown.
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For inverse proportion: x₁ × y₁ = x₂ × y₂. Solve for the unknown.
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Real-life clue: more workers = less time (inverse), more items = more cost (direct).
Worked Example
Problem: If 6 workers can build a wall in 10 days, how many days will 15 workers take?
Solution: Inverse proportion: 6 × 10 = 15 × d. d = 60/15 = 4 days.
Common Mistakes to Avoid
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Confusing direct and inverse proportion — always check the relationship first.
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Using the wrong formula for the type of proportion.
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Not checking if the relationship is truly proportional (it might be neither).
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Forgetting units in the final answer.
Practice Direct and Inverse Proportions on SparkEd
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Frequently Asked Questions
- How do I solve Direct and Inverse Proportions problems?
- Direct proportion: when one quantity increases, the other also increases at the same rate. x/y = constant. Inverse proportion: when one quantity increases, the other decreases. x × y = constant.
- What are common mistakes in Direct and Inverse Proportions?
- Confusing direct and inverse proportion — always check the relationship first. Using the wrong formula for the type of proportion.
- Which class covers Direct and Inverse Proportions?
- Direct and Inverse Proportions is typically taught in Class 8. SparkEd has free practice for all these grades.
- Where can I practise Direct and Inverse Proportions for free?
- SparkEd offers free chapter-wise practice for Direct and Inverse Proportions aligned to CBSE, ICSE, and IB curricula. Visit sparkedmaths.com to start.
SparkEd Maths — sparked.coms@gmail.com — www.sparkedmaths.com