Chapter 13 · Class 10 CBSE · MCQ Test

Statistics MCQ Test — Class 10 CBSE

Practice 10 multiple-choice questions with instant answer reveal and explanations.

Statistics — MCQ Questions

1The mean of 5 numbers is 20. What is the sum of these 5 numbers?

A.80
B.100
C.25
D.4
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Answer: 100

Hint: Mean = Sum / Number of observations. So Sum = Mean x Number.

Solution:

Sum = Mean $\times$ Number of observations — = 20 \times 5 = 100

2The class mark of the class interval $10 - 20$ is:

A.10
B.20
C.15
D.30
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Answer: 15

Hint: Class mark = (upper limit + lower limit) / 2.

Solution:

Class mark $= \frac{10 + 20}{2}$ — = 15

3In a frequency distribution, the sum of $f_i x_i = 420$ and $\sum f_i = 30$. The mean is:

A.12
B.14
C.15
D.16
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Answer: 14

Hint: Mean (direct method) $= \frac{\sum f_i x_i}{\sum f_i}$.

Solution:

Mean $= \frac{\sum f_i x_i}{\sum f_i} = \frac{420}{30}$ — = 14

4The mode of the data: 2, 3, 4, 5, 3, 3, 4, 2, 3 is:

A.2
B.3
C.4
D.5
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Answer: 3

Hint: Mode is the value that appears most frequently.

Solution:

Frequency: 2 appears 2 times, 3 appears 4 times, 4 appears 2 times, 5 appears 1 time.

Mode = 3 (highest frequency).

5The median of the data 3, 8, 5, 7, 6 (when arranged in order) is:

A.5
B.6
C.7
D.8
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Answer: 6

Hint: Arrange in order and find the middle value.

Solution:

Arranged: 3, 5, 6, 7, 8

Middle value (3rd term): — \text{Median} = 6

6What does 'cumulative frequency' mean?

A.Sum of all frequencies up to a certain class
B.The highest frequency
C.The average frequency
D.The difference between consecutive frequencies
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Answer: Sum of all frequencies up to a certain class

Hint: Cumulative means 'adding up' as you go.

Solution:

Cumulative frequency is the running total of frequencies from the first class to the current class.

7The mean of the first 5 natural numbers is:

A.2
B.3
C.4
D.5
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Answer: 3

Hint: First 5 natural numbers: 1, 2, 3, 4, 5.

Solution:

Mean $= \frac{1+2+3+4+5}{5} = \frac{15}{5}$ — = 3

8In the formula for mode of grouped data, $l$ represents:

A.Lower limit of the modal class
B.Length of the class
C.Largest frequency
D.Last class interval
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Answer: Lower limit of the modal class

Hint: The modal class is the class with the highest frequency.

Solution:

In Mode $= l + \left(\frac{f_1 - f_0}{2f_1 - f_0 - f_2}\right) \times h$,

$l$ = lower limit of the modal class.

9If the mean of 6, 8, 5, $x$, 4 is 7, find $x$.

A.12
B.10
C.7
D.15
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Answer: 12

Hint: Sum = Mean x n. Find the sum needed, then solve for $x$.

Solution:

Sum should be $7 \times 5 = 35$.

$6 + 8 + 5 + x + 4 = 35$

$23 + x = 35$ — x = 12

10An ogive is a graph of:

A.Cumulative frequency
B.Frequency
C.Class marks
D.Mean
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Answer: Cumulative frequency

Hint: An ogive is also called a cumulative frequency curve.

Solution:

An ogive (or cumulative frequency curve) plots cumulative frequencies against upper class boundaries.

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Tips for Statistics MCQs

  • 1Read each question carefully and identify what is being asked before looking at the options.
  • 2Try to solve the problem mentally or on paper first, then match your answer with the options.
  • 3Use elimination — rule out clearly wrong options to improve your chances even when unsure.
  • 4Check units, signs, and edge cases — these are common traps in Statistics MCQs.
  • 5Review your mistakes after completing the test to build lasting understanding.

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