Exercise 7.2: Section Formula
Find the point that divides a line segment in a given ratio. The midpoint formula is the special case where the ratio is 1:1.
Extra Practice Questions
These questions cover the same concepts as Exercise 7.2. Try solving them to build confidence before or after the textbook exercise.
The vertices of a triangle are $A(-2, 1)$, $B(5, 4)$, $C(2, -3)$. Find the equation relating coordinates of the centroid.
Find the area of the triangle with vertices $(1, 2)$, $(4, 6)$, and $(5, 2)$.
If the point $P(x, y)$ is equidistant from $A(7, 1)$ and $B(3, 5)$, find the relation between $x$ and $y$.
Find the distance between the points $(0, 0)$ and $(3, 4)$.
The midpoint of the line segment joining $(2, 4)$ and $(6, 8)$ is:
Find the point on the y-axis equidistant from $(-5, -2)$ and $(3, 2)$.
A median of a triangle divides it into two triangles of equal areas. If $A(0, 0)$, $B(6, 0)$, $C(4, 8)$, find the area of each sub-triangle.
Find the midpoint of the segment joining $(-2, 3)$ and $(4, -1)$.
In which quadrant does the point $(-3, 4)$ lie?
The vertices of a triangle are $(2, 1)$, $(5, 2)$, and $(3, 4)$. Find its centroid.
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Try AI Solver — FreeCommon Mistakes to Avoid
- ✗Mixing up m and n in the section formula
- ✗Forgetting that internal and external division use different formulas
- ✗Not simplifying coordinates to simplest form
Other Exercises in Chapter 7
Frequently Asked Questions
What is the section formula?
A point dividing the line joining (x₁,y₁) and (x₂,y₂) in ratio m:n internally is ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).
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