NCERT Solutions Class 6 Maths Chapter 5 — Number Play

Solution:

Step 1: To form the greatest number using given digits, place the largest digit at the thousands place, the next largest at the hundreds place, and so on.

Step 2: The given digits are 7, 0, 8, 3. The largest digit is 8.

Step 3: Arranging them in descending order: 8, 7, 3, 0.

Step 4: Therefore, the greatest 4-digit number is 8730.

Solution:

Step 1: The given number is 5,34,892 in the Indian System.

Step 2: The digit '3' is in the ten thousands place. So, its place value is 3 × 10,000 = 30,000.

Step 3: The face value of the digit '9' is simply 9.

Step 4: The difference between the place value of '3' and the face value of '9' is 30,000 - 9 = 29,991.

Solution:

Step 1: In the International System, numbers are grouped into sets of three digits from the right, separated by commas (e.g., Millions, Thousands, Ones).

Step 2: 'Seventy-five million' means 75,000,000.

Step 3: 'Two hundred nine thousand' means 209,000.

Step 4: 'Four hundred sixteen' means 416. Combining these gives 75,209,416.

Solution:

Step 1: To round a number to the nearest hundred, we look at the digit in the tens place.

Step 2: The number is 2,387. The digit in the tens place is 8.

Step 3: Since 8 is 5 or greater, we round up the hundreds digit. The hundreds digit '3' becomes '4'.

Step 4: All digits to the right of the hundreds place become 0. So, 2,387 rounded to the nearest hundred is 2,400.

Solution:

Step 1: To round a number to the nearest thousand, we look at the digit in the hundreds place.

Step 2: The number of books is 4,567. The digit in the hundreds place is 5.

Step 3: Since 5 is 5 or greater, we round up the thousands digit. The thousands digit '4' becomes '5'.

Step 4: All digits to the right of the thousands place become 0. So, 4,567 rounded to the nearest thousand is 5,000.