Class 8 CBSE Maths Sample Paper 2026 with Solutions

Step 1: A perfect square cannot end with the digits 2, 3, 7, or 8.

Step 2: Let's check the unit digit of each option:

Step 3: 3136 ends in 6 (can be a perfect square, e.g., 56²).

Step 4: 4096 ends in 6 (can be a perfect square, e.g., 64²).

Step 5: 5249 ends in 9 (can be a perfect square, e.g., 73²).

Step 6: 6723 ends in 3. Since a perfect square cannot end in 3, 6723 cannot be a perfect square.

Step 1: A perfect square can only end with the digits 0, 1, 4, 5, 6, or 9.

Step 2: The number 7208 ends with the digit 8.

Step 3: Therefore, 7208 cannot be a perfect square.

Step 4: The other numbers 2401 (ends in 1), 3969 (ends in 9), and 5776 (ends in 6) can be perfect squares. (Specifically, 49², 63², and 76² respectively).

Step 1: The sum of the first 'n' odd natural numbers is given by the formula n².

Step 2: Given that the sum is 2025, we have the equation n² = 2025.

Step 3: To find 'n', we need to calculate the square root of 2025. [n = √2025]

Step 4: By prime factorization or estimation (since 40² = 1600 and 50² = 2500, and 2025 ends in 5, 'n' must end in 5), we find that 45 × 45 = 2025. Thus, n = 45.

Step 1: Using the law $a^m \times a^n = a^{m+n}$:

Step 2: $2^3 \times 2^4 = 2^{3+4}$ [= 2^7]

Step 1: $2^5 \times 2^{-3} \times 2^2 = 2^{5+(-3)+2}$ [= 2^4]

Step 1: $4 = 2^2$ and $32 = 2^5$

Step 2: Numerator: $2^5 \times 3^4 \times 2^2 = 2^7 \times 3^4$

Step 3: Denominator: $3^2 \times 2^5$

Step 4: $= 2^{7-5} \times 3^{4-2} = 2^2 \times 3^2 = 4 \times 9$ [= 36]

Step 1: A rational number is any number that can be written as a fraction p/q, where p and q are integers and q ≠ 0.

Step 2: 3/7 is already in p/q form with p = 3 and q = 7.

Step 3: √2, √5, and π are irrational numbers.

Step 1: LCM of 5 and 3 is 15.

Step 2: Convert: [3/5 = 9/15, -2/3 = -10/15]

Step 3: Add: [9/15 + (-10/15) = -1/15]

Step 1: First product: [3/4 × 8/9 = 24/36 = 2/3]

Step 2: Second product: [2/3 × 9/16 = 18/48 = 3/8]

Step 3: Subtract (LCM = 24): [2/3 - 3/8 = 16/24 - 9/24 = 7/24]

Step 1: A quadrilateral can be divided into two triangles by drawing one of its diagonals.

Step 2: Since the sum of interior angles in each triangle is 180°, the sum of angles in the quadrilateral is the sum of angles of these two triangles.

Step 3: Therefore, the sum of interior angles of a quadrilateral is 180° + 180° = 360°.